Number of moles of `MnO_(4)^(-)` required to oxidise one mole of ferrous oxalate completely in acidic medium will be

Options

A. 2.5 mol
B. 0.2 mol
C. 0.6 mol
D. 0.4 mol

Explanation

The oxidising reaction is:
`2MnO_(4)^(-)+16H^(+)+5C_(2)O_(4)^(2-)rarr2Mn^(2+)+10CO_(2)`
`(2 mol)(5 mol)`
No of moles of `MnO_(4) "required oxidise 1 mole of ferrous oxalate" =5//2 mol=2.5 mol`