Home
Class 11
CHEMISTRY
BeCl(2) + LiAlH(4)...

`BeCl_(2) + LiAlH_(4)`

Text Solution

Verified by Experts

`underset({:("Beryllium"),("chloride"):})(2BeCl_(2)) + underset({:("Lithium"),("aluminium"),("hydride"):})(LiAIH_(4)) to 2BeH_(2) + LiCI + AICI_(3)`
Promotional Banner

Topper's Solved these Questions

  • S-BLOCK ELEMENTS (ALKALI AND ALKALINE EARTH METALS )

    DINESH PUBLICATION|Exercise MCQ|16 Videos

  • S-BLOCK ELEMENTS (ALKALI AND ALKALINE EARTH METALS )

    DINESH PUBLICATION|Exercise VSAQ|28 Videos

  • S-BLOCK ELEMENTS (ALKALI AND ALKALINE EARTH METALS )

    DINESH PUBLICATION|Exercise Matching Types questions|5 Videos

  • REDOX REACTIONS

    DINESH PUBLICATION|Exercise Reasoning Type Questions|4 Videos

  • STATE OF MATTER (GASEOUS AND LIQUID STATE)

    DINESH PUBLICATION|Exercise Ulitmate Preparatory package|20 Videos

Similar Questions

Explore conceptually related problems

Which of the following is reduced most easily to an alkane by NaBH_(4) or LiAlH_(4) ?

Carbon-oxygen double bond are easily reduced by NaBH_(4) or LiAlH_(4) . The actual reducing agent in these reduction is hydride ion (H^(-)) . The metal-hydrogen bond in LiAlH_(4) is more polar than metal-hydrogen bond in NaBH_(4) . As a result LiAlH_(4) is strong reducing agent than NaBH_(4) . Esters, carboxylic acids, amides cannot be reducted by NaBH_(4) . The carbonyl group of amide to methylene group by LiAlH_(4) . underset(D_(2)O)overset(LiAlH_(4))(rarr)'Y' , Identify 'Y' :

Carbon oxygen double bond are easily reduced by NaBH_(4) or LiAlH_(4) . The actual reducing agent in these reduction is hrdride ion (H^(-)) The metal hydrogen bond in LiAlH_(4) is more than polar than metal hydrogen bond in NaBH_(4) . As a result LiAlH_(4) is strong reducing agent than NaBH_(4) . Esters, carboxylic acids, amides cannot be reduced by NaBH_(4) The carbonyl group of amide of reduced to methylene group by LiAlH_(4)

Carbon-oxygen double bond are easily reduced by NaBH_(4) or LiAlH_(4) . The actual reducing agent in these reduction is hydride ion (H^(-)) . The metal-hydrogen bond in LiAlH_(4) is more polar than metal-hydrogen bond in NaBH_(4) . As a result LiAlH_(4) is strong reducing agent than NaBH_(4) . Esters, carboxylic acids, amides cannot be reducted by NaBH_(4) . The carbonyl group of amide to methylene group by LiAlH_(4) . Find the correct product of the following reaction :

Carbon oxygen double bond are easily reduced by NaBH_(4) or LiAlH_(4) . The actual reducing agent in these reduction is hrdride ion (H^(-)) The metal hydrogen bond in LiAlH_(4) is more than polar than metal hydrogen bond in NaBH_(4) . As a result LiAlH_(4) is strong reducing agent than NaBH_(4) . Esters, carboxylic acids, amides cannot be reduced by NaBH_(4) The carbonyl group of amide of reduced to methylene group by LiAlH_(4) Find the correct product of the following reaction:

Carbon oxygen double bond are easily reduced by NaBH_(4) or LiAlH_(4) . The actual reducing agent in these reduction is hrdride ion (H^(-)) The metal hydrogen bond in LiAlH_(4) is more than polar than metal hydrogen bond in NaBH_(4) . As a result LiAlH_(4) is strong reducing agent than NaBH_(4) . Esters, carboxylic acids, amides cannot be reduced by NaBH_(4) The carbonyl group of amide of reduced to methylene group by LiAlH_(4) , Identify X:

In the reaction LiH+AlH_(3) to LiAlH_(4), AlH_(3) and LiH acts as :