Home
Class 11
CHEMISTRY
The solubility of a crystalline compound...

The solubility of a crystalline compound in water is influenced by two factors. These are lattice enthalpy and hydration enthalpy. Lattice enthalpy is needed to separate the ions from the crystal lattice. At the same time hydration enthalpy is released when the ion are dissolved in water. The resultant of these two opposing tendencies guides the solubility of the compound in water. If lattice enthalpy has a greater magnitude, the compound has low solubility. In case hydration enthalpy is more, then the compound is highly soluble in water.
The hydroxide which is maximum soluble in water is :

A

`Be(OH)_(2)`

B

`Mg(OH)_(2)`

C

`Ba(OH)_(2)`

D

`Ca(OH)_(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`Ba(OH)_(2)` is the maximum soluble
Promotional Banner

Topper's Solved these Questions

  • S-BLOCK ELEMENTS (ALKALI AND ALKALINE EARTH METALS )

    DINESH PUBLICATION|Exercise SCP|12 Videos

  • S-BLOCK ELEMENTS (ALKALI AND ALKALINE EARTH METALS )

    DINESH PUBLICATION|Exercise MCR|6 Videos

  • S-BLOCK ELEMENTS (ALKALI AND ALKALINE EARTH METALS )

    DINESH PUBLICATION|Exercise COMPREHESION 2|5 Videos

  • REDOX REACTIONS

    DINESH PUBLICATION|Exercise Reasoning Type Questions|4 Videos

  • STATE OF MATTER (GASEOUS AND LIQUID STATE)

    DINESH PUBLICATION|Exercise Ulitmate Preparatory package|20 Videos

Similar Questions

Explore conceptually related problems

The solubility of a crystalline compound in water is influenced by two factors. These are lattice enthalpy and hydration enthalpy. Lattice enthalpy is needed to separate the ions from the crystal lattice. At the same time hydration enthalpy is released when the ion are dissolved in water. The resultant of these two opposing tendencies guides the solubility of the compound in water. If lattice enthalpy has a greater magnitude, the compound has low solubility. In case hydration enthalpy is more, then the compound is highly soluble in water. A metal M readily forms a water soluble sulphate MSO_(4) water insoluble hydroxide M(OH)_(2) and oxide MO which becomes inert upon heating. The hydroxide is soluble in NaOH. The metal M is

The solubility of a crystalline compound in water is influenced by two factors. These are lattice enthalpy and hydration enthalpy. Lattice enthalpy is needed to separate the ions from the crystal lattice. At the same time hydration enthalpy is released when the ion are dissolved in water. The resultant of these two opposing tendencies guides the solubility of the compound in water. If lattice enthalpy has a greater magnitude, the compound has low solubility. In case hydration enthalpy is more, then the compound is highly soluble in water. A chemical compound 'A' is used for water softening to remove temporary hardness 'A' reacts with Na_(2)CO_(3) to form caustic soda. When CO_(2) is bubbled through 'A' it becomes cloudy. The chemical formula of 'A' is :

Solubility of an ionic compound in water is mainly dependent on: a.Lattice enthalpy , b. Hydration enthalphy Both these factors oppose each other and the resultant of these determines the solubility of an ionic compound in water. If lattce enthalpy has greater value, the compound is less soluble. In case hydration enthalpy has greater value, the compound is highly soluble in water. Which of the following is more soluble in water?

Solubility of an ionic compound in water is mainly dependent on: a.Lattice enthalpy , b. Hydration enthalphy Both these factors oppose each other and the resultant of these determines the solubility of an ionic compound in water. If lattce enthalpy has greater value, the compound is less soluble. In case hydration enthalpy has greater value, the compound is highly soluble in water. Compound is soluble in water if

Solubility of an ionic compound in water is mainly dependent on: a.Lattice enthalpy , b. Hydration enthalphy Both these factors oppose each other and the resultant of these determines the solubility of an ionic compound in water. If lattce enthalpy has greater value, the compound is less soluble. In case hydration enthalpy has greater value, the compound is highly soluble in water. Which of the following is less soluble in water?

Order of lattice enthalpy is as

Solubility of an ionic compound in water is mainly dependent on: a.Lattice enthalpy , b. Hydration enthalphy Both these factors oppose each other and the resultant of these determines the solubility of an ionic compound in water. If lattce enthalpy has greater value, the compound is less soluble. In case hydration enthalpy has greater value, the compound is highly soluble in water. BeF_(2) is soluble in water while fluorides of other alkaline earth metals are insoluble because of:

Solubility of an ionic compound in water is mainly dependent on: a.Lattice enthalpy , b. Hydration enthalphy Both these factors oppose each other and the resultant of these determines the solubility of an ionic compound in water. If lattce enthalpy has greater value, the compound is less soluble. In case hydration enthalpy has greater value, the compound is highly soluble in water. Compound of alkaline earth metals are less soluble than alkali metals, due to:

Enthalpy OF neutralization,lattice enthalpy & its calculation

Write the trend of hydration enthalpies of alkaline earth metal ions.