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PbCl(4) exists but PbBr(4) and PbI(4) do...

`PbCl_(4)` exists but `PbBr_(4)` and `PbI_(4)` do not because of

A

inability of bromine and iodine to oxidise `Pb^(2+)` to `Pb^(4+)`

B

`Br^(-)` and `I^(-)` ions are bigger in size

C

More electronegative nature of bromina and iodine

D

Chlorin e is a gas.

Text Solution

Verified by Experts

The correct Answer is:
A
Inability of bromine and iodine to oxidise `Pb^(2+)` to `Pb^(4+)`.
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