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How many moles of copper will be deposit...

How many moles of copper will be deposited by passing 24125 coulombs of electric current through `CuSO_(4)` solution.

Text Solution

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The correct Answer is:
0.125 mol
`underset(2xx96500" C")(Cu^(2+)(aq))+2e^(-) to underset(1" mol")(Cu(s))`
`=193000" C "`
Moles of copper deposited by passing charge of 193000 coulombs`=1" mol"`
Moles of copper deposited by passing charge of 24125 coulombs
`=(1 mol)xx((24125C))/((193000C))=0.125" mol"`
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