The specific conductivity of `N//50` KCl solution at 298 K is `2.768xx10^(-3)`mho per cm. The resistance of this solutions at 298 K when measured in a particular cell is 250.2 ohm. The resistance of `M//100 CuSO_(4)` solution at 298 K measured with the same cell was 8331 ohm. Calculate the molar conductivity of copper sulphate solution.

Answer

`8.31 S cm^(2)mol^(-1)`

Explanation

Step I. Calculation of cell constant
`R=250.2" ohm", k=2.768xx10^(-3)ohm^(-1) cm^(-1)`
Cell constant `(l//a)=kxxR=(2.768xx10^(-3)ohm^(-1)cm^(-1))xx(250.2" ohm")=0.6925 cm^(-1)`.
Step II. Calculation of molar conductane`(Lambda_(m))=(kxx1000)/(M)`
Specific conductance (k)`=("cell constant")/(R )=((0.6925 cm^(-1)))/((8331" ohm"))=8.31xx10^(-6) ohm^(-1)cm^(-1)`
Molarity of solution (M)=0.01 M
`:. "Molar conductance" (Lambda_(m))=((8.31xx10^(-5)ohm^(-1) cm^(-1))xx(1000" cm"^(3)))/((0.01" mol"))`
`= 831xx10^(-2)ohm^(-1) cm^(2) mol^(-1)=8.31" S " cm^(2) mol^(-1)`.