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The conductivity of 0.20 M solution of K...

The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S `cm^(-1)` . Calculate its molar conductivity.

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The correct Answer is:
`124 S cm^(2)mol^(-1)`
Electrolytic conductivity (specifc conductance) `k=2.48xx10^(-2)Omega^(-1) cm^(-1)`
Molar concentration (M)`=0.20" mol^(-1)`
`Lambda_(M)" " (kxx1000)/(M)=((2.48xx10^(-2)ohm^(-1)cm^(-1))xx(1000 cm^(3)))/((0.2" mol"))=124" ohm"^(-1)cm^(2)mol^(-1)`.
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