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Electorlytic specific conductance of 0.2...

Electorlytic specific conductance of 0.25 mol `L^(-1)` solution of CKI at `25^(@)C` is `2.56xx10^(-2) ohm^(-1)cm^(-1)`. Calculate its molar conductance.

Text Solution

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The correct Answer is:
`102.4 ohm^(-1)cm^(2)mol^(-1)`
` Lambda_(M)=(1000xxk)/(M)=((1000" cm"^(3))xx(2.56xx10^(-2)" ohm"^(-1)cm^(-1)))/((0.25" mol"))=102.4" mol"^(-1)cm^(2)"ohm"^(-1)`.
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