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Molar conductivity of a 1.5 m solustion ...

Molar conductivity of a 1.5 m solustion of an electrolyte is found to be 138.9 S `cm^(2) mol^(-1)`. Calculate the conductivity of this solution.

Text Solution

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The correct Answer is:
`2.083xx10^(-1) S cm^(-1)`
`Lambda_(m)=(1000xxk)/(M),k=(Lambda_(m)xxM)/(1000)=((138.95" cm"^(2)mol^(-1))xx(1.5" mol" " cm"^(-3)))/(1000)=2.083xx10^(-1)" S "cm^(-1)`.
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