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The molar conductance of CH(3)COOHNa HCI...

The molar conductance of `CH_(3)COOHNa` HCI and NaCI at infinite dilutions are 91.0, 426.0 and 126.0 `ohm^(-1) cm^(-1)` respectively. Calculate the molar conductence of acetic acid at infinie dilution.

Text Solution

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The correct Answer is:
`391 ohm^(-1)cm^(2)mol^(-1)`
`Lambda_(m(CH_(3)COOH))^(oo)=Lambda_(m(CH_(3)COONa))^(oo)+Lambda_(m(HCl))^(oo)-Lambda_(m(NaCl))^(oo)`
`=(91.0+426.0-126.0)" ohm"^(-1)cm^(2)mol^(-1)=391" ohm"^(-1)cm^(2)mol^(-1)`.
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