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Lambda((m)(NH(4)OH))^(@) is equal to...

`Lambda_((m)(NH_(4)OH))^(@)` is equal to

A

`Lambda_((m)(NH_(4)OH))^(@)+Lambda_((m)(NH_(4)OH))^(@)-Lambda_((HCl))^(@)`

B

`Lambda_((m)(NH_(4)Cl))^(@)+Lambda_((m)(NaOH))^(@)-Lambda_((NaCl))^(@)`

C

`Lambda_((m)(NH_(4)Cl))^(@)+Lambda_((m)(NaCl))^(@)-Lambda_((NaOH))^(@)`

D

`Lambda_((m)(NaOH))^(@)+Lambda_((m)(NaCl))^(@)-Lambda_((NH_(4)Cl))^(@)`

Text Solution

Verified by Experts

The correct Answer is:
B

Is the corrent answer according to Kohlrausch's Law.
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