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The e.m.f. of the cell : Ni|Ni^(2+)(1...

The e.m.f. of the cell :
`Ni|Ni^(2+)(1.0" M")||Au^(3+)(1.0" M")|Au`
`(E^(@)=-0.25" V " "for " Ni^(2+)//Ni , E^(@)=1.5" V " " for " Au^(3+)//Au)`is

A

`1.25" V "`

B

`-1.25" v "`

C

`1.75" V "`

D

`2.0" V "`

Text Solution

Verified by Experts

The correct Answer is:
C
(c ) e.m.f. of cell `=E_(cathode)^(@)-E_(anode)^(@)`
`=1.5" V " -(-0.25V)=1.75" V "`
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