Home
Class 12
CHEMISTRY
On the basis of information available fr...

On the basis of information available from the reaction
`(4)/(3)Al+O_(2) rarr (2)/(3)Al_(2)O_(3),DeltaG = -827kJ mol^(-1)` of `O_(2)`, the minimum emf required to carry out of the electrolysis of `Al_(2)O_(3)` is `(F=96,500 C mol^(-1))`

A

`2.14" V "`

B

`4.28" V "`

C

`6.42" V "`

D

`8.56" V "`

Text Solution

Verified by Experts

The correct Answer is:
B
(b) `DeltaG=-nFE^(@)`cell.
`E^(@)=(-DeltaG)/(nF)=-((-827000))/(2xx96500)=4.28" V "`
Promotional Banner

Topper's Solved these Questions

  • ALCOHOLS AND PHENOLS

    DINESH PUBLICATION|Exercise COMPLETION QUESTION|2 Videos

  • ALCOHOLS AND PHENOLS

    DINESH PUBLICATION|Exercise NCERT In-Text Questions|9 Videos

  • ALDEHYDES AND KETONES

    DINESH PUBLICATION|Exercise Interger|5 Videos

Similar Questions

Explore conceptually related problems

On the bassis of the information available from the reaction 4/3 Al + O_2 rarr 2/3 Al_2 O_3 . Delta G =- 82 7 k J "mol"^(-1) of O_2 the minimum emf required to carry out an electorlysis of Al_2 O_3 is (F= 96500 C "mol"^(-1))

DeltaG for the reaction : (4)/(3) Al+O_(2)rarr (2)/(3)Al_(2)O_(3) is -772 kJ mol^(-1) of O_(2) . Calculate the minimum EMF in volts required to carry out an electrolysis of Al_(2)O_(3)

Aluminium is obtained by the electrolysis of pure of Al_(2)O_(3) dissolved in

Al_(2)O_(3) reacts with

27 gm of Al will react completely with: 4Al + 3O_(2) rarr 2Al_(2)O_(3)