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Standard reduction potentials for the ha...

Standard reduction potentials for the half reactions are given below :
`F_(2)(g)+2e^(-) to 2F^(-)(aq) , E^(@)=+2.85" V "`
`Cl_(2)(g)+2e^(-) to 2Cl^(-)(aq) , E^(@)=+1.36" V "`
`Br_(2)(g)+2e^(-) to 2Br^(-)(aq) , E^(@)=+1.06" V "`
`I_(2)(g)+2e^(-) to 2I^(-)(aq) , E^(@)=+0.53" V "`
The strongest oxidising and reducing agents respectivity are :

A

`F_(2)` and `I^(-)`

B

`Br_(2)` and `Cl^(-)`

C

`Cl_(2)` and `Br^(-)`

D

`Cl_(2)` and `I_(2)`.

Text Solution

Verified by Experts

The correct Answer is:
A
(a) More negative (or less positive) the value of reduction potential, stranger will be the reducing agent. Thus `l^(-)` is the strongest reducing agent. More positive is the values of reduction potential, stronger will be the oxidising agent. Thus, `F_(2)` is the strongest oxidising agent.
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Standard reduction potentails of the half reactions are given below: F_(2)(g)+2e^(-) rarr 2F^(-)(aq.),, E^(ɵ)= +2.87 Cl_(2)(g)+2e^(-) rarr 2Cl^(-)(aq.),, E^(ɵ)= +1.36 V Br_(2)(g)+2e^(-) rarr 2Br^(-)(aq.),, E^(ɵ)= +1.09 V I_(2)(s)+2e^(-) rarr 2l^(-)(aq.),, E^(ɵ)= +0.54 V The strongest oxidizing and reducing agents respectively are:

Standard reduction potentials of the half reactions are given below {:(F_(2(g))+2e^(-) rarr 2F^(-)""_((aq)),,E^(@)=+2.85V), (Cl_(2(g))+2e^(-) rarr 2Cl^(-)""_((aq)),, E^(@)=+1.36V), (Br_(2(l))+2e^(-) rarr 2Br^(-)""_((aq)),,E^(@)=+1.06V), (l_(2(s))+2e^(-) rarr 2l^(-)""_((aq)),, E^(@)=+0.53V):} The strongest oxidising and reducing agents respectively are