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The conductivity of 0.01 mol L^(-1)KCl s...

The conductivity of 0.01 mol `L^(-1)`KCl solution is `1.41xx10^(-3)" S "cm^(-1)`. What is the molar conductivity (`S cm^(2) mol^(-1)`) ?

A

14.1

B

1.41

C

1410

D

141

Text Solution

Verified by Experts

The correct Answer is:
D
(d) Molar conductivity`(Lambda_(m))=(1000xxk)/(M)`
`=(1000xx(1.41xx10^(-3)" S " cm^(-1)))/((0.01" mol "cm^(-3)))=141" S "cm^(-2)mol^(-1)`
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