The molar conductivity of a `0.5 mol//dm^(3)` solution of `AgNO_(3)` with electrolytic conductivity of `5.76 xx 10^(-3) S cm^(-1)` at `298 K` is

Options

A. `28.8 "S" cm^(2)//mol`
B. `2.88" S "cm^(2)//mol`
C. `11.52" S "cm^(2)//mol`
D. `0.086" S "cm^(2)//mol`

Answer

C

Explanation

(c ) Conductivity (k) `=5.76xx10^(-3)" S "cm^(-1)`
Molar concentration (C )`=0.5" mol " dm^(-3)=((0.5" mol"))/(1000" cm"^(3))`
`=5.0xx10^(14)" mol "cm^(-3)`
Molar conductance`(^^_(m))=(k)/(C )=(5.76xx10^(-3)" S " cm^(-1))/((5.0xx10^(-4)" mol "cm^(-3)))`
`=11.52" S " cm^(2)" mol"^(-1)`