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The limiting molar conductivities Lambda...

The limiting molar conductivities `Lambda^@` for `NaCL, KBr` and `KCI` are ` 126, 152` and `150 S cm^2 ,ol^(-1)` respectively . The `Lambda^@` fro `NaBr S cm^2 "mol"^(-1)` is :

A

`278 " S " cm^(2)mol^(-1)`

B

`176" S " cm^(2)mol^(-1)`

C

`128" S " cm^(2) mol^(-1)`

D

`302" S "cm^(2)mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C

(c ) `Lambda_(NaBr)^(@)=Lambda_(NaCl)^(@)+Lambda_(KBr^(-))^(@)-Lambda_(KCl)^(@)`
`=(126+152-150)=128" S " cm^(2)mol^(-1)`.
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