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Given l//a=0.5 cm^(-1), R= 50 "ohm", N= ...

Given `l//a=0.5 cm^(-1), R= 50 "ohm", N= 1.0.` The equivalent conductance of the electrolytic cell is .

A

`10" ohm"^(-1)cm^(2)(gm" equiv"^(-1))`

B

`20" ohm"^(-1)cm^(2) (gm" equiv"^(-1))`

C

`300" ohm"^(-1) cm^(2)(gm" equiv"^(-1))`

D

`100" ohm"^(-1)cm^(2)(gm "equiv"^(-1))`

Text Solution

Verified by Experts

The correct Answer is:
A
(a) `k=(1)/(a)xx(1)/(R )=(0.5" cm"^(-1))xx((1)/(50)" ohm"^(-1))`
`=0.01" ohm"^(-1)cm^(-1)`
`Lambda_(E)=(kxx100)/(N)=((0.01" ohm"^(-1) cm^(-1))xx(1000 cm^(3)))/((1" gm equiv"))`
`=10" ohm"^(-1)cm^(2)(g" equiv")^(-1)`
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