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The cell , Zn | Zn^(2+) (1M) || Cu^(2+) ...

The cell , `Zn | Zn^(2+) (1M) || Cu^(2+) (1M) Cu (E_("cell")^@ = 1. 10 V)`,
Was allowed to be completely discharfed at `298 K `. The relative concentration of `2+` to `Cu^(2+) [(Zn^(2=))/(Cu^(2+))]` is :

A

`9.65xx10^(4)`

B

Antilog 24.08

C

37.7

D

`10^(37.3)`

Text Solution

Verified by Experts

The correct Answer is:
D
(d) `E_(cell)=E_(cell)^(@)-(0.0591)/(2)"log"[(Zn^(2+))/(Cu^(2+))]`
When cell is completely discharged, `E_(cell)=0`
`:. " " 0=E_(cell)^(@)-(0.0591)/(2)"log"([Zn^(2+)])/([Cu^(2+)])`
`0=1.1-(0.0591)/(2)"log"([Zn^(2+)])/([Cu^(2+)])`
`"log"([Zn^(2+)])/([Cu^(2+)])=(1.1xx2)/(0.0591)=37.3`
`([Zn^2+])/([Cu^(2+)])=10^(37.3)`
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