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Given,{:(E(Fe^(3+) //Fe)^o + 3e Cr E^o ...

Given,`{:(E_(Fe^(3+) //Fe)^o + 3e Cr E^o =- 0.036 V),(E_(Fe^(3+) //Fe)^o =- 0.439 V):}`
The value of standard electrode ptoential for the charge,

A

`-0.072" V "`

B

`0.385" V "`

C

`0.770" V "`

D

`-0.270" V "`

Text Solution

Verified by Experts

The correct Answer is:
C
(c ) Given `Fe^(3+)+3e^(-) to Fe , E_(1)^(@)=-0.36" V "`
`Fe^(2+)+2e^(-) to Fe, " " E_(2)^(@)=-0.439" V "`
Required equation is :
`Fe^(3+)+e^(-) to Fe^(2+), " " E_(3)^(@)=?`
Appying `DeltaG^(@)=-nFE_(cell)^(@)`
`DeltaG_(3)^(@)=DeltaG_(1)^(@)-DeltaG_(2)^(@)`
`(-n_(3)FE_(3 cell))=-(n_(1)FE_(1 cell)^(@))-(-n_(2)FE_(2 cell)^(@))`
`E_(3cell)^(@)=3E_(1 cell)^(@)-(-2E_(cell)^(@))`
`E_(3cell)^(@)=3xx(-0.036)-(2xx-0.439)`
`=(-0.08)+(0.878)=0.77" V "`.
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