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A conductivity cell has been calibrited ...

A conductivity cell has been calibrited with 0.01 M electrolyte solution (`k=1.25xx10^(-3)" S "cm^(-1)`) in the cell and the measured resistance is 800 ohms at `25^(@)C`. The cell constant will be :

A

`1.02 cm^(-1)`

B

`0.102 cm^(-1)`

C

`1.00 cm^(-1)`

D

`0.5 cm^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
(c ) Specific conductance (k) `=(1)/(R )xx(1)/(a)`
`(l)/(a)=kxxR`
`=(1.25xx10^(-3)" ohm"^(-1)cm^(-1))xx(800" ohm")`
`=1.0 cm^(-1)`
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