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The emf of a galvanic cell constituted w...

The emf of a galvanic cell constituted with the electrodes `Zn^(2+)//Zn(E^(@)=-0.76" V")` and `Fe^(2+)//Fe(E^(@)=-0.41" V")` is :

A

`-0.35" V"`

B

`+1.17" V"`

C

`+0.35" V"`

D

`-1.17" V"`

Text Solution

Verified by Experts

The correct Answer is:
C
(c ) `E_(cell)^(@)=E_(cathode)^(@)-E_(anode)^(@)`
`=(-0.41)-(-0.76)=0.35" V"`
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