Home
Class 12
CHEMISTRY
Two electrolytic cells containing molten...

Two electrolytic cells containing molten solutions of Nickel chloride and Aluminium chloride are connected in series.If same amount of electric current is passed through them, what will be the weight of Nickel obtained when 18 gm of Aluminium is obtained ? (`Al-27" gm"//"mole", Ni-58.5" gm"//"mole"^(-1)`)

A

58.5 g

B

29.25 g

C

117 g

D

5.85 g

Text Solution

Verified by Experts

The correct Answer is:
A

(a) According to Farady's second law of electrolysis
`("Mass of Ni deposited")/("Mass of Al deposited")=("Equivalent mass of Ni")/("Equivalent mass of Al")`
`=((58.5//2 g " equiv"^(-1)))/((27.0//3 g "equiv"^(-1)))`
Mass of Ni deposited `=((18 g)xx(29.25))/((9.0))=58.5 g`
Promotional Banner

Topper's Solved these Questions

  • ALCOHOLS AND PHENOLS

    DINESH PUBLICATION|Exercise COMPLETION QUESTION|2 Videos
  • ALCOHOLS AND PHENOLS

    DINESH PUBLICATION|Exercise NCERT In-Text Questions|9 Videos
  • ALDEHYDES AND KETONES

    DINESH PUBLICATION|Exercise Interger|5 Videos

Similar Questions

Explore conceptually related problems

Two electrolytic cells containing molten solutions of nickel chloride and aluminium chloride are connected in series. If same amount of electric current is passed through them, what will be the weight of nickel obtained when 18 g of aluminium is obtained ? ( Al = 27 g mol^(-1) , Ni = 58.5 g mol^(-1) )

The same mass of aluminium is draw into two wires 1mm and 2mm thick . Two wires are connected in series and current is passed through them. Heat produced in the wires is in the ratio.

Two electrolytic cells containing silver nitrate solution and dilute sulphuric acid solution were connected in series. A steady current of 2.5 amp was passed through them till 1.078 g of silver was deposited. [Ag=107.8 g mol^(-1) ,1 F=96,500 C] (i) How much electricity was consumed ? (ii) What was the weight of oxygen gas liberated ?

The amount of Aluminium deposited when 0.1 Faraday current is passed through aluminium chloride will be (R=27)