Home
Class 12
CHEMISTRY
The correct order of equivalent conducta...

The correct order of equivalent conductance at infinite dilution of `LiCl, NaCl` and `KCl` is:

A

`LiCl gt NaCl gt KCl`

B

`KCl gt NaCl gt LiCl`

C

`NaCl gt KCl gt LiCl`

D

`LiCl gt KCl gt NaCl`

Text Solution

Verified by Experts

The correct Answer is:
B
(b) The ionic character decreases as :
`KCl gt NaCl gt LiCl`
Promotional Banner

Topper's Solved these Questions

  • ALCOHOLS AND PHENOLS

    DINESH PUBLICATION|Exercise COMPLETION QUESTION|2 Videos

  • ALCOHOLS AND PHENOLS

    DINESH PUBLICATION|Exercise NCERT In-Text Questions|9 Videos

  • ALDEHYDES AND KETONES

    DINESH PUBLICATION|Exercise Interger|5 Videos

Similar Questions

Explore conceptually related problems

Conductors allow the passage of electric current through them. Metallic and electrolytic are the two type of conductors. Current carriers in metallic and electrolytic conductors are free electrons and free ions respectively. Specific conductance or consuctivity of the electrolyte solution is given by the following relation : kappa=c xx l/A where, c=1//R is the conductance and l//A is the cell constant. Molar conductance (Lambda_(m)) and equivalence conductance (Lambda_(e)) of an electrolyte solution are calculated using the following similar relations : Lambda_(m)= kappa xx 1000/M Lambda_(e)= kappa xx 1000/N Where, M and N are the molarity and normality of the solution respectively. Molar conductance of strong electrolyte depends on concentration : Lambda_(m)=Lambda_(m)^(@)-b sqrt(c) where, Lambda_(m)^(@)= molar conductance at infinite dilution c= concentration of the solution b= constant The degrees of dissociation of weak electrolytes are calculated as : alpha=Lambda_(m)/Lambda_(m)^(@)=Lambda_(e)/Lambda_(e)^(@) The correct order of equivalent conductances at infinite dilution of LiCl, NaCl and KCl is :

The correct order of molar conductivity at infinite dilution of LiCl, NaCl and KCl is

The equivalent conductance at infinite dilution of a weak acid such as HF

The equivalent conductances at infinite dilution of HCl and NaCl are 426.15 and 126.15 mho cm^(2) g eq^(-1) respectively. It can be said that the mobility of :