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The half cell reaction for rusting of ir...

The half cell reaction for rusting of iron are:
`2H^(+)+2e^(-)+(1)/(2)O_(2)rarrH_(2)O(l), E^(@)=+1.23V`
`Fe^(2+)+2e^(-)rarrFe(s), E^(@)=-0.44V`
`DeltaG^(@)` (in KJ) for the reaction is

A

`-76`

B

`-322`

C

`-161`

D

`-152`.

Text Solution

Verified by Experts

The correct Answer is:
B
(b) `Fe(s) to Fe^(2+)+2e^(-),DeltaG_(1)^(@)`
`2H^(+)+2e^(-)+1//2 O_(2) to H_(2)O(l) , DeltaG_(2)^(@)`
`Fe(s)+2H^(+)+1//2 O_(2) to Fe^(2+)+H_(2)O(l),DeltaG_(3)^(@)`
`DeltaG_(3)^(@)=DeltaG_(2)^(@)+DeltaG_(1)^(@)`
`=[-2Fxx(+0.44)]+[-2Fxx(1.23)]`
`=[-2xx96500xx(+0.44)+[-2xx96500xx1.2]`
`=-84920-237390`
`=-322310" CV"=-322310" J"=-322.31" kJ"`
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