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Assertion (A): For a Daniell cell : Zn...

Assertion `(A):` For a Daniell cell `:`
`Zn|Zn^(2+)||Cu^(2+)|Cu` with `E_(cell)=1.1V`, the application of opposite potential greater than `1.1V` results into the flow of electron from cathod to anode. Reason `(R):` Zn is deposited at anode and Cu is dissolved at cathode

A

If both assertion and reason are correct and reason is correct explanation for assertion.

B

If both assertion and reason are correct but reason is not correct explanation for assertion.

C

If assertion is correct but reason is incorrect.

D

If assertion and reason both are incorrect.

Text Solution

Verified by Experts

The correct Answer is:
B
(b) Correct explanation. The cell will work in opposite direction. Cu will be oxidised to `Cu^(2+)` ions. The electrons released will move towards anode and will be taken by `Zn^(2+)` ions to form Zn(s). It will be deposited at the anode.
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For the Daniell cell Zn| Zn^(2+) || Cu^(2+) | Cu with The questions consist of two statements each, printed as Assertion and Reason. While answering these questions you are required to choose any one of the following four responses : E_(cell) = 1.1 V , the application of oposite potential grater than 1.1 V results into folow of electron from Cu to Zn . Zn is deposited at anode and Cu is deposited at cathode .

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