One coulomb of charge passes through a solution of `AgNO_(3)` and `CuSO_(4)` connected in series and the concentration of the two solutions is in the ratio `1:2`. The ratio by weight of Ag and Cu deposited on Pt electrode is :

Options

A. `107.9:63.54`
B. `54:31.77`
C. `107.9:31.77`
D. `54:63.54`

Answer

C

Explanation

(c ) According to Faraday's second law of electrolysis
`("Weight of Ag deposited")/("Equivalent weight of Ag")=("Weight of Cu deposited")/("Equivalent weight of Cu")`
`(W_(Ag))/(W_(cu))=(E_(Ag))/(E_(Cu))=(107 g)/((163.54)//2)=(107.9)/(31.77)`

or `107.9:31.77`