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For the cell reaction, Cu(C(2))^(2+)(aq)...

For the cell reaction, `Cu_(C_(2))^(2+)(aq)+Zn(s) to Zn_(C_(1))^(2+)(aq)+Cu(s)`
The change in free energy `(DeltaG)` at a given temperature is a function of :

A

In `C_(1)`

B

In `(c_(2)//c_(1))`

C

In `(c_(1)+c_(2))`

D

In `c_(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
(b) `-DeltaG=nFE_(cell)=nFE_(cell)^(@)+RT" In "([Cu^(2+)])/([Zn^(2+)])`
`-DeltaG` is a function of In `(C_(2)//C_(1))`
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