In the reaction
`BrO^(-3)(aq) + 5Br^(-) (aq) + 6H^(+) rarr 3Br_(2)(1) + 3H_(2)O(1)`
The rate of appearance of bromine `(Br_(2))` is related to rate of disapperance of bromide ions as folllwoing :

Explanation

`BrO_(3)^(-)(aq)+5Br^(-)(aq) + 6H^(+) (aq) to 3Br_(2)(l) + 3H_(2)O(l)`
`BrO_(3)^(-)(aq)+5Br^(-)(aq) + 6H^(+) (aq) to 3Br_(2)(l) + 3H_(2)O(l)`
Rate of reaction in terms of `Br^(-)` ions and `Br_(2)` is:
Rate (r) = `-1/5 (d[Br^(-)])/(dt) = 1/3 (d[Br_(2)])/(dt)`
`(d[Br_(2)])/(dt) = -3/5(d[Br^(-)])/(dt)`