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For the reaction N(2)O(5) rarr 2NO(2) + ...

For the reaction `N_(2)O_(5) rarr 2NO_(2) + (1)/(2) O_(2)`, the rate of disappearance of `N_(2)O_(5)` is `6.25 xx 10^(-3) "mol L"^(-1) s^(-1)`. The rate of formation of `NO_(2)` and `O_(2)` will be respectively.

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Rate = `(-d[N_(2)O_(5)])/(dt)=1/2 (d[NO_(2)])/(dt)=(2d[O_(2)])/(dt)`
`(d[NO_(2)])/(dt) = (2d[N_(2)O_(5)])/(dt) = 2 xx(6.25xx10^(-3))=1/25 xx 10^(-2)mol L^(-1)s^(-1)`
`(d[O_(2)])/(dt) = 1/2(d[N_(2)O_(5)])/(dt) = 1/2 xx (6.25 xx 10^(-3))= 3.125 xx 10^(-3) mol L^(-1)s^(-1)`
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