For the reaction
`N_(2)(g) +3H_(2)(g) to 2NH_(3)(g)`
If `Delta[NH_(3)]//Deltat= 4 xx 10^(-8)mol L^(-1)s^(-1)`, what is the value of `Delta[H_(2)]//Deltat`=?

Explanation

Rate of reaction = `(-d[N_(2)])/(dt) = -1/3 (d[H_(2)])/(dt) = 1/2(d[NH_(3)])/(dt)`
`(d[H_(2)])/(dt) =-3/2(d[NH_(3)])/(dt) = -3/2 xx (4 xx 10^(-4) mol L^(-1)s^(-1))`
`=-6 xx 10^(-4)mol L^(-1)s^(-1)`.