Consider the following data for the reaction:
`A+B to`Products

Determine the order of reaction with respect to A and with respect to B and the overall order of the reaction.

Explanation

The rate law may be expressed as:
Rate = `k[A]^(p)[B]^(q)`
Comparing experiments 2 and 3,
`(Rate)_(2) = (k[0.2]^(p)[2.0]^(q))/(K[0.2]^(p)[1.0]^(q))= (8.4 xx 10^(-3))/(8.4 xx 10^(-3))=1`
`[2]^(q) = [2]^(0),q=0`
Comparing experiments 1 and 2,
`(Rate)_(2) = k[0.20]^(p)[1.0]^(q) = 8.4 xx 10^(-3)`
`(Rate)_(1) = k[0.10]^(p)[1.0]^(q) = 2.1 xx 10^(-3)`
Dividing eqn. (iii) by (iv),
`(Rate)_(2)/(Rate_(1)) = (k[0.20]^(p)[1.0]^(q))/(k[0.10]^(p)[1.0]^(q)) = (8.4 xx 10^(-3))/(2.1 xx 10^(-3))=4`
Order w.r. to A = 2, B=0, Overall order = 2.