Find out two-third `(2//3)` life of a first order reaction in which `k=5.48 xx 10^(-14)s^(-1)`

Explanation

To find the two-third life of a first-order reaction with a rate constant \( k = 5.48 \times 10^{-14} \, s^{-1} \), we can follow these steps:

### Step 1: Understand the Concept of Two-Third Life
The two-third life of a reaction refers to the time taken for two-thirds of the initial concentration to react. If we denote the initial concentration as \( A \), then two-thirds of \( A \) is \( \frac{2}{3}A \). Therefore, the remaining concentration after two-thirds has reacted will be \( A - \frac{2}{3}A = \frac{1}{3}A \).

### Step 2: Use the First-Order Kinetics Equation
For a first-order reaction, the relationship between concentration and time is given by the equation:
\[
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