The rate constant for a reaction of zero order in A is `0.0030 mol L^(-1)s^(-1)`. How long will take for the initial concentration to fall from 0.10 M to 0.075 M?

Explanation

For zero order reaction,
`[A]_(t) = -kt + [A]_(0)`
`[A]_(t) = 0.075 mol L^(-1), k = 0.03 mol L^(-1) s^(-1)`
`0.075 mol L^(-1)s^(-1)= 0.075 -0.10) = -0.025 mol L^(-1) , [A]_(0) =0.10 mol L^(-1) k ==0.03 mol L^(-1)s^(-1)`
`[0.075 mol L^(-1)] = (-t) xx 0.003 mol L^(-1)s^(-1) + 0.10 mol L^(-1)`.
`(-t) xx (0.03 mol L^(-1)s^(-1) + mol L^(-1)`
`(-t) xx (0.03 mol L^(-1)s^(-1)) = (0.075 -0.10) = -0.025 mol L^(-1)`
`t = -0.025 mol L^(-1)/(-0.03 mol L^(-1)s^(-1)) = 8.3`s