In a reaction, `2A to` Products, the concentration of A decreases from 0.5 mol `L^(-1)` to 0.4 mol `L^(-1)` in 10 minutes. Calculate the rate during this interval.

Explanation

To calculate the rate of the reaction \(2A \rightarrow \text{Products}\) when the concentration of \(A\) decreases from \(0.5 \, \text{mol L}^{-1}\) to \(0.4 \, \text{mol L}^{-1}\) over a time interval of \(10\) minutes, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Change in Concentration**:
- Initial concentration of \(A\) = \(0.5 \, \text{mol L}^{-1}\)
- Final concentration of \(A\) = \(0.4 \, \text{mol L}^{-1}\)
- Change in concentration (\(\Delta [A]\)) = Final concentration - Initial concentration
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