The conversion of the molecules X to Y follows second order kinetics. If concentration of X is increased three times, how will it affect the rate of formation of Y?

Explanation

for the reaction `XtoY`.
Reaction rate ( r) = `k[X]^(2)`
If the cocentration be increased to three times, then
Reaction rate `r^(')= k[X]^(2)`
If the concentration be increased to three times, then
Reaction rate `(r^(')) = k[3X]^(2)`
`r^(')/r = (k[3X]^(2))/(k[X]^(2)) = 9`
`therefore` the rate formation of Y will increase to nine times because the reaction rate has increased to nine times.