A reaction is second order with respect to a reaction. How is the rate of reaction affected if the
(a) doubled, (b) reduced to `1//2`?

Explanation

Let the reaction , `Ato` products.
Reaction rate (r ) = `k[A]^(2)` (for second order reaction)
i) When concentration is doubled, the rate of reaction may be expressed as:
Reaction rate `(r^(')) = k[2A]^(2)`
`r^(')//r = (k[2A]^(2))/(k[A]^(2))=4 or r^(')= 4r`
reaction rate becomes four times.
ii) When concentration is reduced to half, the rate of reactioin may be expressed as: Reaction rate `(r^('')) = (k[A//2]^(2))/(k[A]^(2)) = 1//4 or r^('') = 1//4r`
reaction rate will be reduced to `1//4`.