The decomposition of hydrocarbon follows the equation `k=(4.5xx10^(11)s^(-1))e^(-28000K//T)`
Calculate `E_(a)`.

Explanation

According to Arrhenius equation, `k= Ae^(-Ea//RT)`
According to given data, `k= (4.5 xx 10^(11) s^(-1))e^(-28000k//T)`
On comparing, `-E_(a)/(RT) = -28000/T K`
or `E_(a) = (28000 K) xx ( R) = (28000 K)/T`
or `E_(a) = (28000 K) xx ( R) = (28000 K) xx 8.314 J K^(-1) mol^(-1) = 232.792 kJ mol^(-1)`