i) Write the mathematics expressions relating the variation of the rate constant of a reaction with temperatures.
ii) How can you graphically find the activation energy of the reaction from the above expression?
iii) The slope of the line in the graph of log k(k=rate constant) versus `1//T` is `-5841`. Calculate the activation energy of the reaction.

Explanation

i) N//A
ii) N//A
iii) Slope =`(E_(a))/(2.303R)` or `E_(a) = -("slope") xx 2.303 R`
`E_(a) = -(-5814) xx (2.303 xx 8.314 J mol^(-1))`