From the given figure:
i) Calculate `DeltaE` for the reaction and energy of activation for the forward reaction and energy of activation for the backward reaction.
ii) The dotted curve is in the presence of a catalyst, what is the energy of activation for the two reactions in the presence of the catalyst?
iii) will the catalyst change the extent of the reaction?

Explanation

i)For the uncatalysed reaction, represented by upper curve
Energy of the reaction `(E_(r))= 110 kJmol^(-1)`
Energy of the products `(E_(p)) = 100 kJmol^(-1)`
`therefore` Change in the internal energy `(DeltaE) = E_(p) -E_(R )`
`=140-110=30kJmol^(-1)`
Energy of activation for the reverse reaction `(E_(a)(f) = E^(0)-E_(p)`
`140-100 = 40 kJ mol^(-1)`
ii) For the catalyst reaction, represented by lower curve,
`E_(a)(f) = E^(0) - E_(r) = 120-110 = 10 kJmol^(-1)`
`E_(a)(b) = E^(0)-E_(p) = 120-100 = 20 kJmol^(-1)`
iii) There will no effect on the extent for the reaction because the activation energies for the forward reactions have decreased equally.