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For the reaction 2N(2)O(5) rarr 4NO(2)+O...

For the reaction `2N_(2)O_(5) rarr 4NO_(2)+O_(2)` rate of reaction and rate constant are `1.02 xx 10^(-4)` and `3.4 xx 10^(-5) sec^(-1)` respectively. The concentration of `N_(2)O_(5)` at that time will be

A

1.732

B

3

C

`1.02 xx 10^(-4)`

D

`3.4 xx 10^(5)`

Text Solution

Verified by Experts

The correct Answer is:
B

b) `[N_(2)O_(5)]= ("Rate")/k = (1.2 xx 10^(-4) mol L^(-1)s^(-1))/(3.4 xx 10^(-5)s^(-1))`=3
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