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If 60 % of a first order reaction was co...

If 60 % of a first order reaction was completed in 60 minutes, 50 % of the same reaction would be completed in approximately
[log = 4 = 0.60, log 5 = 0.69].

A

45 minutes

B

60 minutes

C

40 minutes

D

50 minutes.

Text Solution

Verified by Experts

The correct Answer is:
A
a) `k=(2.303)/(60"min") log 100/40=0.0153 min^(-1)`
`t_(1//2) = 0.693/k = 0.693/(0.0153 min^(-1))`
=45.23 min
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