Consider the reaction:
`N_(2(g))+3H_(2(g))rarr 2NH_(3(g))`.
The equally relationship between `-(d[NH_(3)])/(dt)` and `-(d[H_(2)])/(dt)` is:

Options

A. `(d[NH_(3)])/(dt) = (-d[H_(2)])/(dt)`
B. `(d[NH_(3)])/(dt) = -1/3(d[H_(2)])/(dt)`
C. `(d[NH_(3)])/(dt) = -2/3 (d[H_(2)])/(dt)`
D. `(d[NH_(3)])/(dt) = -3/2 (d[H_(2)])/(dt)`

Answer

C

Explanation

c) is the correct relation.