In a zero order reaction, for every `10^(@)` rise of temperaure, reaction rate is doubled. If the temperature `10^(@)`C to `100^(@)`C, the reaction rate will become:

Options

A. 256 times
B. 512 times
C. 64 times
D. 128 times

Answer

B

Explanation

b) For every `10^(@)` rise in temperature, reaction rate increase by 2.
`(r_(100^(@))C)/(r_(10^(@))C) = 2^((100-10))/(10) = 2^(9)=512` times.