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In a first order reaction, the concentra...

In a first order reaction, the concentration of the reactant decreases from 0.6 M to 0.3 M in 30 minutes. The time taken for the concentration to change from 0.1 M to 0.025 M is

A

50 min

B

30 min

C

15 min

D

60 min

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The correct Answer is:
To solve the problem, we need to analyze the first-order reaction and use the information provided to find the time taken for the concentration to change from 0.1 M to 0.025 M. ### Step-by-Step Solution: 1. **Identify the Initial and Final Concentrations:** - Initial concentration (C1) = 0.1 M - Final concentration (C2) = 0.025 M 2. **Determine the Half-Life of the Reaction:** - We know from the question that the concentration decreases from 0.6 M to 0.3 M in 30 minutes. This represents a 50% reduction in concentration, which corresponds to one half-life (t₁/₂). - Therefore, the half-life (t₁/₂) = 30 minutes. 3. **Calculate the Number of Half-Lives Required:** - From 0.1 M to 0.05 M is one half-life (30 minutes). - From 0.05 M to 0.025 M is another half-life (30 minutes). - Thus, the total change from 0.1 M to 0.025 M involves 2 half-lives. 4. **Calculate the Total Time Taken:** - Total time = Number of half-lives × Duration of each half-life - Total time = 2 × 30 minutes = 60 minutes. ### Final Answer: The time taken for the concentration to change from 0.1 M to 0.025 M is **60 minutes**. ---

To solve the problem, we need to analyze the first-order reaction and use the information provided to find the time taken for the concentration to change from 0.1 M to 0.025 M. ### Step-by-Step Solution: 1. **Identify the Initial and Final Concentrations:** - Initial concentration (C1) = 0.1 M - Final concentration (C2) = 0.025 M ...
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