For the reaction X-Y, the concentration of X are `1.2` M, `0.6`M, order of reaction is:

Options

A. Zero
B. Half
C. one
D. two

Answer

C

Explanation

c) `underset("Initialtime")1.2M to underset("1 hr")0.6M to underset(2 hr)0.3M to underset(3 hr)0.15 M`
`t_(1//2) = 1hr`.
For the nth order reaction.
`(t_(1//2))_(1)/(t_(1//2))_(2) = ([A_(0)]_(2)^(n-1))/([A_(0)]_(1)^(n-1))`
`1=(6/3)^(n-1)` or `(2)^(0) = (2)^(n-1)`
n-1=0 or n=1
Order of reaction is one.