A graph plotted between `log t_(50%)` vs log concentration in a straight line. What conclusion can you draw from this graph?

Options

A. n= 1, `t_(1//2)= t/(x xx a)`
B. `n=2, t_(1//2) = 1/a`
C. `n=1, t_(1//2)= 0.693/k`
D. none of these

Answer

C

Explanation

c) `t_(1//2) propto a^(1-n) = k(a)^(1-n)`
log `t_(1//2) = log k + (1-n) log a`
The graph is expected to be a straight line.
Therefore, slope 1-n =0 or n=1