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The difference rate law for the reaction...

The difference rate law for the reaction
`H_(2) +I_(2) to 2HI` is

A

`-(d[H_(2)])/(dt) = (-d[I_(2)])/(dt) = (-d[HI])/(dt)`

B

`(-d[H_(2)])/(dt) = (d[I_(2)])/(dt) = 1/2 (d[HI])/(dt)`

C

`1/2(d[H_(2)])/(dt) = 1/2 (d[I_(2)])/(dt) = -(d[HI])/(dt)`

D

`-2 (dH_(2)]/(dt)`

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The correct Answer is:
D
d) is the correct answer.
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