For the reaction system `2NO(g) + O_(2)(g) rarr 2NO(g)` volume is suddenly produced to half its value by increasing the pressure on it. If the reaction is of first order with respect to `O_(2)` and second order with respect to `NO`. The rate of reaction will

Options

A. diminish to one-eighth of its reaction wil
B. Increase to eight times of its initial value.
C. Increase to four times of its initial value.
D. diminish to one-fourth of its initial value.

Answer

B

Explanation

b) Rate ( r) = `k[NO]^(2)[O_(2)]`
When the volume is reduced to half `(1//2)`, the concentration will become double.
New rate ( r) = `k[2NO]^(2)[2O_(2)]`
`=8k[NO]^(2)[O_(2)]`
New rate will be 8 times the old rate.