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For a reaction 1//2A to 2B, rate of disa...

For a reaction `1//2A to 2B`, rate of disappearance of A is related to the rate of appearance of B by the expression:

A

`(-d[A])/(dt) = 4(d[B])/(dt)`

B

`(-d[A])/(dt) = 1/4(d[B])/(dt)`

C

`(-d[A])/(dt) = 1/4 (d[B])/(dt)`

D

`-(d[A])/(dt) = (d[B])/(dt)`

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To solve the problem regarding the relationship between the rate of disappearance of A and the rate of appearance of B for the reaction \( \frac{1}{2}A \rightarrow 2B \), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Reaction**: The given reaction is \( \frac{1}{2}A \rightarrow 2B \). Here, A is the reactant and B is the product. 2. **Define Rate of Reaction**: The rate of a reaction can be defined in terms of the change in concentration of reactants and products over time. 3. **Rate of Disappearance of A**: The rate of disappearance of A can be expressed as: \[ \text{Rate of disappearance of A} = -\frac{1}{\Delta t} \frac{\Delta [A]}{\Delta t} = -\frac{1}{2} \frac{\Delta [A]}{\Delta t} \] Here, the negative sign indicates that the concentration of A is decreasing. 4. **Rate of Appearance of B**: The rate of appearance of B can be expressed as: \[ \text{Rate of appearance of B} = \frac{1}{\Delta t} \frac{\Delta [B]}{\Delta t} = \frac{1}{2} \frac{\Delta [B]}{\Delta t} \] 5. **Relate the Rates**: According to the stoichiometry of the reaction, we can relate the rate of disappearance of A to the rate of appearance of B: \[ -\frac{1}{2} \frac{\Delta [A]}{\Delta t} = \frac{1}{2} \frac{\Delta [B]}{\Delta t} \] 6. **Rearranging the Equation**: To express the relationship in a more straightforward manner, we can rearrange the equation: \[ \frac{\Delta [A]}{\Delta t} = -\frac{1}{2} \frac{\Delta [B]}{\Delta t} \] This indicates that for every 1 mole of A that disappears, 2 moles of B appear. 7. **Final Expression**: Therefore, the final relationship between the rates can be expressed as: \[ \frac{-\Delta [A]}{2 \Delta t} = \frac{\Delta [B]}{2 \Delta t} \] or simply: \[ \text{Rate of disappearance of A} = \frac{1}{2} \times \text{Rate of appearance of B} \]

To solve the problem regarding the relationship between the rate of disappearance of A and the rate of appearance of B for the reaction \( \frac{1}{2}A \rightarrow 2B \), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Reaction**: The given reaction is \( \frac{1}{2}A \rightarrow 2B \). Here, A is the reactant and B is the product. 2. **Define Rate of Reaction**: The rate of a reaction can be defined in terms of the change in concentration of reactants and products over time. ...
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